In a reaction excess of H_(2)O is added to 0.1 mole of acidified KMnO_(4) solution. Then the S.T.P volume of O_(2) liberated is

In a reaction excess of H_(2)O is added to 0.1 mole of acidified KMnO_

1.	In a reaction excess of H_(2)O is added to 0.1 mole of acidified KMnO_(4) solution. Then the S.T.P volume of O_(2) liberated is
Answer» 5.6 lit. 6.6 lit. 11.2 lit. 22.4 lit. Solution :2 moles of `KMnO_(4) rarr 5 " MOLE "O_(2) UARR` 2 moles `KMnO_(4) rarr 5 times 22.4 L` 0.1 mole `KMnO_(4) rarr ?=5.60L`