1.

In a reaction vessel, 100 g H_(2) and 100 g Cl_(2) are mixed and suitable conditions are provided for the reaction: H_(2(g))+Cl_(2(g))to2HCl_((g)) The amount of HCl formed in this reaction (at 100% yield) will be

Answer»

`102.8g`
`73g`
`36.5g`
`142g`

Solution :`UNDERSET(2g)(H_(2(g)))+underset(71g)(Cl_(2(g)))rarrunderset(73g)(2HCl_((g)))`
`100G underset("reagent")underset("limiting")(100g)`
100% YIELD of HCl `=(100xx73)/(71)=102.8g`
90% yield of HCl = `(90)/(100)xx102.8=92.53g`


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