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In a reaction vessel, 100 g H_(2) and 100 g Cl_(2) are mixed and suitable conditions are provided for the reaction: H_(2(g))+Cl_(2(g))to2HCl_((g))The amount of HCl formed (at 90% yield) will be |
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Answer» `36.8g` `100g underset("REAGENT")underset("limiting")(100g)` 100% yield of HCl `=(100xx73)/(71)=102.8g` 90% yield of HCl = `(90)/(100)xx102.8=92.53g` |
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