1.

In a reaction vessel, 100 g H_(2) and 100 g Cl_(2) are mixed and suitable conditions are provided for the reaction: H_(2(g))+Cl_(2(g))to2HCl_((g))The amount of HCl formed (at 90% yield) will be

Answer»

`36.8g`
`62.5g`
`80g`
`92.53g`

SOLUTION :`underset(2g)(H_(2(g)))+underset(71g)(Cl_(2(g)))rarrunderset(73g)(2HCl_((g)))`
`100g underset("REAGENT")underset("limiting")(100g)`
100% yield of HCl `=(100xx73)/(71)=102.8g`
90% yield of HCl = `(90)/(100)xx102.8=92.53g`


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