1.

In a reversible reaction the rate constants of the forward and the backward reactions are 4.8xx10^(-5)s^(-1)and1.2xx10^(-4)s^(-1) respectively. Calculate the equilibrium constant.

Answer»

SOLUTION :`K=k_(1)/k_(2)=(4.8xx10^(-5))/(1.2xx10^(-4))=0.4`


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