1.

In a saturated solution of the sparingly soluble strong electrolyte AgIO_(3) (Molecular mass = 283), the equilibrium which sets in is AgIO_(3) (s) hArr Ag^(+) (aq) +IO_(3)^(-) (aq) If the solubility product constant K_(sp) of AgIO_(3) at a given temperature is 1.0xx10^(-8), what is the mass of AgIO_(3) contained in 100 ml of its saturated solution ?

Answer»

`1.0xx10^(-4)g`
`28.3xx10^(-2)g`
`2.83xx10^(-3)g`
`1.0xx10^(-7)g`

Solution :`{:("AgIO"_(3),HARR,"Ag"^(+),+,"IO"_(3)^(-)),(,,S,,S):}`
`K_(sp)=S^(2) or S=sqrt(K_(sp))=sqrt(10^(-8))=10^(-4) "mol" L^(-1)`
`=10^(-4)xx283 gL^(-1) = 2.83 xx 10^(-2) g L ^(-1)`
Thus, 1000 mL of the saturated solution will contain `AgIO_(3)=2.83xx10^(-2)g`
`:.100 ` m L of the saturated solution will contain
`AgIO_(3)=2.83xx10^(-3)g`.


Discussion

No Comment Found