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In a saturated solution of the sparingly soluble strong electrolyte AgIO_(3) (Molecular mass = 283), the equilibrium which sets in is AgIO_(3) (s) hArr Ag^(+) (aq) +IO_(3)^(-) (aq) If the solubility product constant K_(sp) of AgIO_(3) at a given temperature is 1.0xx10^(-8), what is the mass of AgIO_(3) contained in 100 ml of its saturated solution ? |
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Answer» `1.0xx10^(-4)g` `K_(sp)=S^(2) or S=sqrt(K_(sp))=sqrt(10^(-8))=10^(-4) "mol" L^(-1)` `=10^(-4)xx283 gL^(-1) = 2.83 xx 10^(-2) g L ^(-1)` Thus, 1000 mL of the saturated solution will contain `AgIO_(3)=2.83xx10^(-2)g` `:.100 ` m L of the saturated solution will contain `AgIO_(3)=2.83xx10^(-3)g`. |
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