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In a saturated solution of the spatingly soluble strong electrolyte `AgIO_(3)` (molecular mass `=283`) the equilibrium which sets in is `AgIO_(3) (s)hArrAg^(+)(aq)+IO_(3)^(-)(aq)` If the solubility product constant `K_(SP)` of `AgIO_(3)` at a given temperature is `1.0xx10^(-8)`, what is the mass of `AgIO_(3)` cotained in `100 mL` of its saturated solution?A. `28.3 xx 10^(-2) g`B. `2.83 xx 10^(-3) g`C. `1.0 xx 10^(-7) g`D. `1.0 xx 10^(-4) g` |
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Answer» Correct Answer - B `AgIO_(3)(s) hArr Ag^(+)(aq) + IO_(3)^(-)(aq)` Let the solubility of `AgIO_(3)` be s `K_(sp) = [Ag^(+)][IO_(3)^(-)]` `1.0 xx 10^(-8) = S^(2)` `S = 10^(-4) "mol"//"lit"` `= (10^(-4) xx283)/(1000) xx 100 = 283 xx 10^(-5)` `= 2.83 xx 10^(-3) g//100 ml` |
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