InterviewSolution
Saved Bookmarks
| 1. |
In a saturated solution of the spatingly soluble strong electrolyte `AgIO_(3)` (molecular mass `=283`) the equilibrium which sets in is `AgIO_(3) (s)hArrAg^(+)(aq)+IO_(3)^(-)(aq)` If the solubility product constant `K_(SP)` of `AgIO_(3)` at a given temperature is `1.0xx10^(-8)`, what is the mass of `AgIO_(3)` cotained in `100 mL` of its saturated solution?A. `1.0 xx 10^(-4)g`B. `28.3 xx 10^(-2)g`C. `2.83 xx 10^(-3)g`D. `1.0 xx 10^(-7)g` |
|
Answer» Correct Answer - C `AgIO_(3)hArr underset(s)(Ag^(+))+underset(s)(IO_(3)^(-))` `K_(sp)=s^(2)` or `s=sqrt(K_(sp))=sqrt(10^(-8))-10^(-4)mol L^(-1)` `=10^(-4) xx 283 g L^(-1) =2.83 xx 10^(-2) g L^(-1)` Thus 1000 mL of the saturated solution will contain `AgIO_(3)=2.83 xx 10^(-2)g` `:. `100 mL of the saturated solution will contain `AgIO_(3)=2.83 xx10^(-3)g` |
|