InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
In a single-slit diffraction experiment, a monochromatic source of light of wavelength 'lamda' illuminates a narrow slit of width 'a'. Show, giving appropriate reasoning, that the half angular width of the central maximum in the observed pattern is (nearly) equal to (lamda)/(a). |
|
Answer» Solution :In a single-slit diffraction experiment, at the CENTRE point on the SCREEN we get central diffraction maxima. The first diffraction minima is given by the condition `asintheta=pmlamda or sintheta=pm(lamda)/(a)` If `theta` is small then `sintheta=theta=pm(lamda)/(a)` It SHOWS that central diffraction maxima extends from `theta=0` to `theta=pm(lamda)/(a)`. it means that the HALF ANGULAR width of the central maxima in diffraction pattern is `(lamda)/(a)`. |
|