InterviewSolution
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InterviewSolution
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In a single state transistor amplifier, when the signal changes by `0.02 V` the base current by `10 mu A` and collector current by `1 mA`. If collector load `R_(C) = 2k Omega` and `R_(L) = 10 k Omega`, Calculate : (i) Current Gain (ii) Input Impedance, (iii) Effective `AC` load, (iv) Voltage gain and (v) Power gain.A. `50,2k Omega,1.66 k Omega,83,8300`B. `100,1 k Omega,1.66 Omega,83,8300`C. `100, 2k Omega,1.66 k Omega,83,830`D. `100,2 k Omega,1.66 k Omega,83.8300` |
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Answer» Correct Answer - D (i) Current Gain `beta -(delta i_(c))/(delta i_(b))` (ii) Input impedance `R_(i)=(delta V_(BE))/(delta i_(b))` (iii) Effective (ac) load `R_(AC)=(R_(C)R_(L))/(R_(C)+R_(L))` (iv) Voltage gain `A_(v)=beta xx (R_(AC))/(R_(i n))` (v) Power gain, `A_(p) = A_(v) xx beta`. |
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