In a single throw of a pair of dice, the probability of getting the su

1.	In a single throw of a pair of dice, the probability of getting the sum a perfect square isA \(\frac1{18}\)B \(\frac7{36}\)C \(\frac1{6}\)D \(\frac2{9}\)
Answer» Total numbers of elementary events are: 6 x 6 = 36 Let E be the event of getting a perfect square Favorable outcomes are: 4, 9 4 and 9 can be rolled in combinations of: (2,2), (1,3), (3,1) , (3,6), (4,5), (5,4), (6,3) Numbers of favorable outcomes are = 7 P (perfect square) = P (E) = \(\frac{7}{36}\)

In a single throw of a pair of dice, the probability of getting the sum a perfect square isA \(\frac1{18}\)B \(\frac7{36}\)C \(\frac1{6}\)D \(\frac2{9}\)

Answer»

Total numbers of elementary events are: 6 x 6 = 36

Let E be the event of getting a perfect square

Favorable outcomes are: 4, 9 4

and 9 can be rolled in combinations of: (2,2), (1,3), (3,1) , (3,6), (4,5), (5,4), (6,3)

Numbers of favorable outcomes are = 7

P (perfect square) = P (E) = \(\frac{7}{36}\)

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In a single throw of a pair of dice, the probability of getting the sum a perfect square isA \(\frac1{18}\)B \(\frac7{36}\)C \(\frac1{6}\)D \(\frac2{9}\)

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