In a solid AB, A atoms have a ccp arrangement and B atoms occupy all the octahedral sites. If all the face-centred atoms along one of the axes passing through body centres are removed, then what will be the resultant stoichiometry of compound ?

In a solid AB, A atoms have a ccp arrangement and B atoms occupy all t

1.	In a solid AB, A atoms have a ccp arrangement and B atoms occupy all the octahedral sites. If all the face-centred atoms along one of the axes passing through body centres are removed, then what will be the resultant stoichiometry of compound ?
Answer» Number of A atoms constituting ccp=4 (1 from 8 corners and 3 from 6 face centres ) On removing two face centes along one of the axis Number of A atoms left in unit cell = 3 Number of B atoms occupying all octahedral voids =4 (3 from 12 edges centes and 1 froms body centre ) Hence, formula of compound is `A_3B_4` and stoichiometry is = 3:4

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In a solid AB, A atoms have a ccp arrangement and B atoms occupy all the octahedral sites. If all the face-centred atoms along one of the axes passing through body centres are removed, then what will be the resultant stoichiometry of compound ?

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