In a solid, oxide ions are arranged in ccp. One-sixth of the tetrahedral voids are occupied by the cations A while one-third of the octahedral voids are occupied by the cations B. What is the formula of the compound?

In a solid, oxide ions are arranged in ccp. One-sixth of the tetrahedr

1.	In a solid, oxide ions are arranged in ccp. One-sixth of the tetrahedral voids are occupied by the cations A while one-third of the octahedral voids are occupied by the cations B. What is the formula of the compound?
Answer» Solution :Suppose `O^(2-)` ions=n. Then octahedral voids=n and TETRAHEDRAL voids= 2n. Cations A=`1/6xx2n=n/3`CATION B=`1/3xxn=n/3` `THEREFORE` A:B:`O^(2-)=n/3:n/3:n=1:1:3` , i.e., FORMULA is `ABO_3`