In a solid S^(2-) ions are packed in fcc lattice. Zn^(2+) occupy half of the tetrahedral voids in an alternating arrangement. Now if a plane is cut (as shown) then the cross -section would be

In a solid S^(2-) ions are packed in fcc lattice. Zn^(2+) occupy half

1.	In a solid S^(2-) ions are packed in fcc lattice. Zn^(2+) occupy half of the tetrahedral voids in an alternating arrangement. Now if a plane is cut (as shown) then the cross -section would be
Answer» Solution :`S^(2-)` ion FORM fcc LATTICE `rarr ZN^(+2)` ion ocupy ALTERNATE four TETRAHEDRAL void i.e.