InterviewSolution
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InterviewSolution
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In a solution , 0.02 M acetic acid is 4% dissociation . The `[OH^(-)]` in the solution isA. `8 xx 10^(-4)`B. `2xx10^(-14)`C. `8xx10^(10)`D. `1.25 xx 10^(-11)` |
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Answer» Correct Answer - D `[H^(+)]=sqrt(alpha^(2)C^(2))=sqrt((0.02)^(2)*(0.04)^(2))=8xx10^(-4)` `[H^(+)][OH^(-)]=10^(-14)` `:. [OH^(-)]=(10^(-14))/(8xx10^(-4))=1.25xx10^(-11)M` |
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