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In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 respectively. What will be the end correction?A. 1.05 cmB. 115.5 cmC. 92.5 cmD. 113.5 cm |
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Answer» Correct Answer - A For end correction x , `(l_(2)+x)/(l_(1)+x)=( 3lambda//4)/(lambda//4)=3 ` ` implies x=(l_(2)-3l_(1))/(2)` `=(70.2-3 xx 22.7)/(2)=1.05 cm` |
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