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In a solution of 7.8 g benzene `(C_(6)H_(6))` and 46.0 g toluene `(C_(6)H_(5)CH_(3))` the mole fraction of benzene is :A. `1//6`B. `1//5`C. `1//2`D. `1//3` |
Answer» Correct Answer - A Mole fraction of `C_(6)H_(6)=(7.8//78)/(7.8/78+46/92)=1/6` |
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