1.

In a solution of 7.8 gm benzene `C_(6)H_(6)` and 46.0 gm toluene `(C_(6)H_(5)CH_(3))`, the mole fraction of benzene in this solution isA. `1//6`B. `1//5`C. `1//2`D. `1//3`

Answer» Correct Answer - A
Mole fraction at `C_(6)H_(6)=((7.8)/(78))/((7.8)/(78)+(46)/(92))=(1)/(6)`.


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