In a solution the concentration of CaCl_(2) is 5M & that of MgCl_(2) is 5 m. The specific gravity of solution is 1.05, calculate the concentration of Cl^(-) in the solution in terms of Molarity.

In a solution the concentration of CaCl_(2) is 5M & that of MgCl_(2) i

1.	In a solution the concentration of CaCl_(2) is 5M & that of MgCl_(2) is 5 m. The specific gravity of solution is 1.05, calculate the concentration of Cl^(-) in the solution in terms of Molarity.
Answer» Solution :`CaCl_(2)rarr5M=555g` in `1L` solution or in `1050g` solution `wt`. Of `("solvant" + MgCl_(2))=1050-555=495g` `MgCl_(2)rarr5m` `1000G` solvant`rarr 5` MOL of `MgCl_(2)` `=5xx95=475gMgCl_(2)` `i.e., 1475 ("solvant" + MgCl_(2))rarr 475g MgCl_(2)` `495("solvant"+ MgCl_(2)) rarr(475)/(1475)xx495` `=159.4g MgCl_(2)` MOLES of `MgCl_(2)=(159.4)/(95)=1.678` TOTAL moles of `Cl^(-)` `=(5+1.678)xx2=13.356` volume of solution `1L` Molarity of`Cl^(-) = 13.356 M`