1.

In a standing wave formed by two atoms separated by 1.21Å, there are 3 nodes and 2 antinodes. Find its wavelength.

Answer»

`1.21 Å`
`2.42Å`
`6.05Å`
`3.63Å`

Solution :
Here n= no.of CLOSED loops = no. of antinodes =2
Now, `LAMDA _(n) = (2L)/(n) = ( 2 xx 1.21 )/(2) 1.21 Å`


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