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In a tennis match Maria Sharapova returns an incoming ball at an angle that is `4°` below the horizontal at a speed of `15 m//s`. The ball was hit at a height of 1.6 m above the ground. The opponent, Sania Mirza, reacts 0.2 s after the ball is hit and runs to the ball and manages to return it just before it hits the ground. Sania runs at a speed of `7.5 m//s` and she had to reach 0.8 m forward, from where she stands, to hit the ball. (a) At what distance Sania was standing from Maria at the time the ball was returned by Maria? Assume that Maria returned the ball directly towards Sania. (b) With what speed did the ball hit the racket of Sania? `[g = 9.8 m//s^(2)]` |
Answer» Correct Answer - (a) `12.13 m` (b) `16 m//s` |
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