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In a thermal reactor the mean lifetime of one generation of thermal neutrons is `tau=0.10 s`. Assuming the multiplication constant to be equal to `k=1.010`, find : (a) how many times the number of neutrons in the reactor, and consequently its power, will increase over `t=1.0 mi n` , (b) the period `T` of the reactor, i.e., the time period over which its power increases `e-fold. |
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Answer» (a) This number is `K^(n-1)` where `n=` no. of generations in time `t=t//T` Substitution gives `388`. (b) We write `k^(n-1)=e^(((T)/(tau)-1)In k)` or `(T)/(tau)-1=(1)/(In k)` and `T=tau(1+(1)/(In k))=10.15 sec` |
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