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Employing the uncertainty principle, estimate the minimum kinetic energy of an electron confined within a region whose sizes is `l=0.20nm`. |
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Answer» Clearly `Deltax le l" so" Delta p_(x),ge(ħ)/(l)` Now `p_(x)geDeltaP_(x)` and so `T=(p_(x)^(2))/(2m) ge (ħ^(2))/(2ml^(2))` Thus `T_(min)=(ħ^(2))/(2m l^(2))~=0.95eV` |
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