In a thermodynamic process helium gas obeys the law TP^(-2//5) = constant. If temperature of2 moles of the gas is raised from T to 3T, then :

In a thermodynamic process helium gas obeys the law TP^(-2//5) = const

1.	In a thermodynamic process helium gas obeys the law TP^(-2//5) = constant. If temperature of2 moles of the gas is raised from T to 3T, then :
Answer» HEAT given to the gas is 9RT Heat given to the gas is zero Increase in INTERNAL ENERGY is 6RT Work done by the gas is - 6RT Answer :B::C::D