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In a thermodynamic process on an ideal monoatomic gas, the infinitesimal heat absorbed by the gas is given by TΔX, where T is temperature of the system and ΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monoatomic ideal gas X=32R ln(TTA)+R ln(VVA). Here, V is volume of gas, TA and VA are constants. The List - I below gives some quantities involved in a process and List - II gives some possible values of these quantities. List - IList - II(i) Work done by the system in process 1→2→3(P)13RT0ln2(ii)Change in internal energy in process1→2→3(Q)13RT0(iii)Heat absorbed by the system in process1→2→3(R)RT0(iv) Heat absorbed by the system in process1→2(S)43RT0(T)13RT0(3+ln2)(U)56RT0 If the process carried out on one mole of monoatomic ideal gas is as shown in figure in the PV diagram with P0V0=13RT0. The correct match is- |
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Answer» In a thermodynamic process on an ideal monoatomic gas, the infinitesimal heat absorbed by the gas is given by TΔX, where T is temperature of the system and ΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monoatomic ideal gas X=32R ln(TTA)+R ln(VVA). Here, V is volume of gas, TA and VA are constants. The List - I below gives some quantities involved in a process and List - II gives some possible values of these quantities. |
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