In a throw of a fair die, find the probability of getting(i) the numbe

1.	In a throw of a fair die, find the probability of getting(i) the number 5 (ii) the number 3 or 4 (iii) a prime number (iv) a number greater than 4 (v) a number greater than 6 (vi) a number less than 6
Answer» Outcomes (X) = 1,2,3,4,5,6 (i)The number 5 appers only once in a throw of dice So P(X)= 1/6 (ii) There are either chances of getting 3 or 4 P(X) = 2/6 (iii) Prime Number:- a number which is divisible by 1 or number itself. So favourable cases are 2,3,5 P(X) = 3/6 (iv) Number greater than 4 are 5,6 so P(X) = 2/5 (v) A Dice contains only n1,2,3,4,5,6 as the number, so there is no chance of getting a number than 6 So P(X)=0 (vi) Since A Dice contains only n1,2,3,4,5,6 as the number So Number, less than 6 is P(X) = 5/6

In a throw of a fair die, find the probability of getting(i) the number 5 (ii) the number 3 or 4 (iii) a prime number (iv) a number greater than 4 (v) a number greater than 6 (vi) a number less than 6

Answer»

Outcomes (X) = 1,2,3,4,5,6

(i)The number 5 appers only once in a throw of dice So P(X)= 1/6

(ii) There are either chances of getting 3 or 4 P(X) = 2/6

(iii) Prime Number:- a number which is divisible by 1 or number itself.

So favourable cases are 2,3,5 P(X) = 3/6

(iv) Number greater than 4 are 5,6 so P(X) = 2/5

(v) A Dice contains only n1,2,3,4,5,6 as the number, so there is no chance of getting a number than 6 So P(X)=0

(vi) Since A Dice contains only n1,2,3,4,5,6 as the number So Number, less than 6 is P(X) = 5/6

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