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In a transistor in `CE` configuration, the ratio of power gain to voltage gain isA. `alpha`B. `beta//alpha`C. `beta alpha`D. `beta` |
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Answer» Correct Answer - D For `CE` configuration voltage gain `=betaxxR_(L)//R_(i)` Power gain `=beta^(2)xxR_(L)//R_(i) implies (Power gai n)/(Vol tag e gai n) =beta` |
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