In a trapezium ABCD, O is the point of intersection of AC and BD, AB || CD, and AB=52×CD. The area of AOB=100 cm2. The area of ΔOCD is :[1 mark]

In a trapezium ABCD, O is the point of intersection of AC and BD, AB

1.	In a trapezium ABCD, O is the point of intersection of AC and BD, AB \|\| CD, and AB=52×CD. The area of AOB=100 cm2. The area of ΔOCD is :[1 mark]
Answer» In a trapezium ABCD, O is the point of intersection of AC and BD, AB \|\| CD, and $A B = \frac{5}{2} \times C D$ . The area of $A O B = 100 c m^{2}$ . The area of $Δ O C D$ is : [1 mark]