InterviewSolution
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InterviewSolution
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In a triangle `A B C ,/_C=pi/2dot`If `tan(A/2)a n dtan(B/2)`are the roots of the equation `a x^2+b x+c=0,(a!=0),`then the value of `(a+b)/c`(where `a , b , c ,`are sides of ``opposite to angles `A , B , C ,`respectively) is |
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Answer» Correct Answer - 1 `tan ((A)/(2)) + tan ((B)/(2)) = - (b)/(a)` `tan ((A)/(2)) xx tan ((B)/(2)) = (c ) /(a)` `A + B = 90^(@) or (A+B)/(2) = 45^(@)` `rArr tan ((A+B)/(2)) =1= (-(b)/(a))/(1-(c )/(a))` or `1- (c )/(a) = - (b)/(a)` or ` a +b = c` or `(a+b)/(c ) =1`. |
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