In a triangle ABC, if a2+b2a2−b2sin(A−B)=1 and the triangle is not – InterviewSolution

1.	In a triangle ABC, if a2+b2a2−b2sin(A−B)=1 and the triangle is not right angled, then cos(A−B)=
Answer» In a triangle $A B C,$ if $\frac{a^{2} + b^{2}}{a^{2} - b^{2}} sin (A - B) = 1$ and the triangle is not right angled, then $cos (A - B) =$

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