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In a triangle ABC with ∠A=90∘, P is a point on BC such that PA : PB = 3:4. If AB √7 and AC = √5, then BP:PC is |
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Answer» In a triangle ABC with ∠A=90∘, P is a point on BC such that PA : PB = 3:4. If AB √7 and AC = √5, then BP:PC is |
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