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In a Triangle PQR if ∠Q = 3 ∠R = 2 (∠P +∠R) then value of ∠Q will be 1. 110° 2. 120° 3. 40° 4. 102° |
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Answer» Correct option is 2. 120° Q = 3R = 2(P + R) Q = 2P + 2R 3R = 2P + 2R R = 2P ∴ Q = 2P + 4P = 6P ∴ P + 6P + 2P = 180° ⇒ 9p = 180° ⇒ p = 20° ∴ Q = 6 × 20 = 120° |
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