1.

In a Triangle PQR if  ∠Q = 3 ∠R = 2 (∠P +∠R) then value of ∠Q will be 1. 110° 2. 120° 3. 40° 4. 102°

Answer»

Correct option is  2. 120°

Q = 3R = 2(P + R) 

Q = 2P + 2R 

3R = 2P + 2R 

R = 2P

∴ Q = 2P + 4P = 6P

∴ P + 6P + 2P = 180° ⇒ 9p = 180° ⇒ p = 20°

∴ Q = 6 × 20 = 120°



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