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In a twin – wire transmission line in air, the adjacent voltage maximum are at 12.5cm and 27.5cm. The operating frequency is (a) 300 MHz (b) 1 GHz (c) 2 GHz (d) 6.28 GHz |
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Answer» Correct option (b) 1 GHz Explanation: Distance between adjacent voltage maximum λ/2 = 27.5 -12.5 = 15cm λ = 30cm Velocity of propagation on twin – wire TL line v = 3 x 108m/sec f = v/λ = (3 x 108)/(30 x 10-2) = (3 x 1010)/30 = (30 x 109)/30Hz = 1GHz |
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