1.

In a twin – wire transmission line in air, the adjacent voltage maximum are at 12.5cm and 27.5cm. The operating frequency is (a) 300 MHz (b) 1 GHz (c) 2 GHz (d) 6.28 GHz

Answer»

Correct option (b) 1 GHz

Explanation:

Distance between adjacent voltage maximum

 λ/2 = 27.5 -12.5
= 15cm

λ = 30cm

Velocity of propagation on twin – wire TL line

v = 3 x 108m/sec

f = v/λ = (3 x 108)/(30 x 10-2)

= (3 x 1010)/30 = (30 x 109)/30Hz

= 1GHz



Discussion

No Comment Found

Related InterviewSolutions