In a two digit number, the ten’s digit is bigger. The product of the

1.	In a two digit number, the ten’s digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number.
Answer» Given, the difference between two digits is 6 and the ten's digit is bigger than the unit's digit. So, let the unit's digit be x and ten's digit be (x + 6). From the given condition, we have: x(x + 6) = 27 x² + 6x − 27 = 0 x² + 9x − 3x − 27 = 0 x(x + 9) − 3(x + 9) = 0 (x + 9) (x − 3) = 0 x = −9, 3 Since, the digits of a number cannot be negative. So, x = 3. Unit's digit = 3 Ten's digit = 9 Thus, the number is 93.

In a two digit number, the ten’s digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number.

Answer»

Given, the difference between two digits is 6 and the ten's digit is bigger than the unit's digit.

So, let the unit's digit be x and ten's digit be (x + 6).

From the given condition, we have:

x(x + 6) = 27

x² + 6x − 27 = 0

x² + 9x − 3x − 27 = 0

x(x + 9) − 3(x + 9) = 0

(x + 9) (x − 3) = 0

x = −9, 3

Since, the digits of a number cannot be negative. So, x = 3.

Unit's digit = 3

Ten's digit = 9

Thus, the number is 93.