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in a two wattmeter method of measurement of 3 power the two wattmeter readings are 1000w,2000w .The reactive power of the circuit is​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>The <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> Wattmeter Method is explained, taking an example of a <a href="https://interviewquestions.tuteehub.com/tag/balanced-389334" style="font-weight:bold;" target="_blank" title="Click to know more about BALANCED">BALANCED</a> load. In this, we have to prove that the power measured by the Two Wattmeter i.e. the sum of the two wattmeter readings is equal to root 3 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> of the phase voltage and line voltage (√3VLIL Cosϕ) which is the actual power <a href="https://interviewquestions.tuteehub.com/tag/consumed-2540963" style="font-weight:bold;" target="_blank" title="Click to know more about CONSUMED">CONSUMED</a> in a 3 phase balanced load.</p><p></p><p></p><p></p></body></html>


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