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In a wire, when elongation is 2cm, energy stored is E. If it is stretched by 10 cm, then the energy stored will beA. EB. 2 EC. 4 ED. 25 E |
Answer» Correct Answer - D `(E_(2))/(E_(1))=((x_(2))/(x_(1)))^(2)=((10)/(2))^(2)=25` `E_(2)=25E_(1)`. |
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