1.

In a wire, when elongation is 2cm, energy stored is E. If it is stretched by 10 cm, then the energy stored will beA. EB. 2 EC. 4 ED. 25 E

Answer» Correct Answer - D
`(E_(2))/(E_(1))=((x_(2))/(x_(1)))^(2)=((10)/(2))^(2)=25`
`E_(2)=25E_(1)`.


Discussion

No Comment Found

Related InterviewSolutions