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In a YDSE green light of wavelength 500 nm is used. Where will be the second bright fringe be formed for a set up in which separation between slits is 4 mm and the screen is placed 1 m from the slits? |
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Answer» `y_(2)=(2lambdaD)/d=(2xx500xx10^(-9)xx1)/(4xx10^(-3))=0.25 mm` Note: While reporting our answer we should report `y_(2)=pm0.25mm` as fringe will be formed both above and below central bright fringe. |
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