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In a Young’s double slit experiment, 16 fringes are observed in a certain segment of the screen when light of a wavelength 700 nm is used. If the wavelength of light is changed to 400 nm, the number of fringes observed in the same segment of the screen would be(1) 28 (2) 24 (3) 30 (4) 18 |
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Answer» Answer is (1) 28 N1λ1 = N2λ2 16 × 700 = N2 × 400 ⇒ N2 = 28 Just use this formula and solveN1λ1 = N2λ2 16 × 700 = N2 × 400 ⇒ N2 = 28 |
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