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In a young’s double slit experiment, D equals the distance of screen from the plane of slits and d is the separation between the slits. The distance of the nearest point from the central maximum on the screen, where the intensity is same as that due to a single slit, is equal toGiven that dD=10−4,λ=6000 ˙A |
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Answer» In a young’s double slit experiment, D equals the distance of screen from the plane of slits and d is the separation between the slits. The distance of the nearest point from the central maximum on the screen, where the intensity is same as that due to a single slit, is equal to Given that dD=10−4,λ=6000 ˙A |
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