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In a Young's experiment, the distance between two slits is 0.2 mm. If the wavelength of light used in this experiment is 5000 Å, then the distance of 3rd bright fringes from central maxima will be ......

Answer» <html><body><p>`0.75`<br/>`0.075`<br/>`0.0075`<br/>`0.057`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For `<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>^(th)` <a href="https://interviewquestions.tuteehub.com/tag/bright-391129" style="font-weight:bold;" target="_blank" title="Click to know more about BRIGHT">BRIGHT</a>, <a href="https://interviewquestions.tuteehub.com/tag/fringe-1000590" style="font-weight:bold;" target="_blank" title="Click to know more about FRINGE">FRINGE</a>, <br/> In `d sin theta= n lambda` <br/> `n=3, d=0.2 cm lambda=5xx10^(-5) cm` <br/> `:. sin theta=(n lambda)/(d)=(3xx5xx10^(-5))/(0.02)` <br/> `sin theta=(0.015)/(2)=0.0075` <br/> `:. sin theta =0.0075` <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a></body></html>


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