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In ∆ABC, DE ║ BC such that AD/DB = 3/5 . If AC = 5.6cm, then AE = ? (a) 4.2cm (b) 3.1cm (c) 2.8cm (d) 2.1cm |
Answer» (d) 2.1 cm It is given that DE || BC. Applying Thales’ theorem, we get: AD/DB = AE/EC Let AE be x cm. Therefore, EC = (5.6 – x) cm ⇒ 3/5 = x/5.6 − x ⇒ 3(5.6 − x) = 5x ⇒ 16.8 − 3x = 5x ⇒ 8x = 16.8 ⇒ x = 2.1 cm |
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