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In ∆ABC right angled at B, if tan A= √3, then cos A cos C- sin A sin C = (a) -1(b) 0(c) 1(d) √3/2 |
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Answer» Correct answer is: (b) 0 tan A= √3 = tan 60° so ∠A=60°, Hence ∠C = 30°. So cos A cos C- sin A sin C = (1/2)x (√3/2) - (√3/2)x (1/2) =0 |
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