In above question, what will be the speed of the particle on the ring which is at the same height as that of the centre?

In above question, what will be the speed of the particle on the ring

1.	In above question, what will be the speed of the particle on the ring which is at the same height as that of the centre?
Answer» v 2v `vsqrt2` zero Solution :Velocity of the given particle is v in the horizontal direction due to TRANSLATION and v in the vertical direction due to ROTATION. Hence RESULTANT velocity of this particle becomes `vsqrt2` and option (E) is correct.