1.

In adiabatic process, the pressure is increased by 2//3%. Ifgamma=3//2then the volume decreases by nearly –

Answer»

`(4)/(9)%`
`(2)/(3)%`
`1%`
`(9)/(4)%`

Solution :For adiabatic process
`(DeltaP)/(DeltaV)=-(gammaP)/(V)`
`(DeltaP)/(P) xx 100 = -gamma (DeltaV)/(V)xx 100 =(2)/(3)`
`(DeltaV)/(V) xx 100 = -(1)/(gamma) xx (2)/(3)`
`= -(2)/(3) xx (2)/(3) = -(4)/(9)%`


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