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In adiabatic process, the pressure is increased by 2//3%. Ifgamma=3//2then the volume decreases by nearly – |
Answer» <html><body><p>`(4)/(9)%` <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(3)%` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>%` <br/>`(9)/(4)%` </p>Solution :For adiabatic process <br/> `(DeltaP)/(DeltaV)=-(gammaP)/(V)` <br/> `(DeltaP)/(P) xx <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> = -gamma (DeltaV)/(V)xx 100 =(2)/(3)` <br/> `(DeltaV)/(V) xx 100 = -(1)/(gamma) xx (2)/(3)`<br/> `= -(2)/(3) xx (2)/(3) = -(4)/(9)%`</body></html> | |