In alkaline conditions, KMnO_(4) reacts as follows, 2KMnO_(4) + 2KOH to 2K_(2)MnO_(4)+H_(2)O + [O] Therefore, its equivalent mass will be :

In alkaline conditions, KMnO_(4) reacts as follows, 2KMnO_(4) + 2KOH

1.	In alkaline conditions, KMnO_(4) reacts as follows, 2KMnO_(4) + 2KOH to 2K_(2)MnO_(4)+H_(2)O + [O] Therefore, its equivalent mass will be :
Answer» 31.6 52.7 72 `158.0` SOLUTION :N//A