1.

In Ammonia molecule the bond angle is 107°18 and in water molecule it is 104°35′, although in both the central atoms are sp3 hybridized Explain.

Answer»

i. The ammonia molecule has sp3 hybridization.The expected bond angle is 109°28′. But the actual bond angle is 107°28′. 

It is due to the following reasons.

  • One lone pair and three bond pairs are present in ammonia molecule.
  • The strength of lone pair-bond pair repulsion is much higher than that of bond pair-bond pair repulsion.
  • Due to these repulsions, there is a small decrease in bond angle (~2°) from 109°28′ to 107°18′.

ii. The water molecule has sp3 hybridization. The expected bond angle is 109°28′. But the actual bond angle is 104°35′. 

It is due to the following reasons.

  • Two lone pairs and two bond pairs are present in water molecule.
  • The decreasing order of the repulsion is Lone pair-Lone pair > Lone pair-Bond pair > Bond pair-Bond pair.
  • Due to these repulsions, there is a small decrease in bond angle (~5°) from 109°28′ to 104°35′.


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