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In an A.P. the pth term is q and the (p + q)th term is 0. Then the qth term is(A) – p(B) p (C) p + q (D) p – q |
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Answer» (B) is the correct answer Let a, d be the first term and common difference respectively Therefore, Tp = a + (p – 1) d = q and ... (1) Tp+ q = a + (p + q – 1) d = 0 ... (2) Subtracting (1), from (2) we get qd = – q Substituting in (1) we get a = q – (p – 1) (–1) = q + p – 1 Now Tq = a + (q – 1) d = q + p – 1 + (q – 1) (–1) = q + p – 1 – q + 1 = p |
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