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In an A.P the sum of the first n terms bears a constant ratio `lamda` with the sum of the next n terms then `lamda` =A. `1/2`B. `1/3`C. `1/4`D. `2/5` |
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Answer» Correct Answer - 2 a,a + d,a+ 2d……… in A.P `lambda=("the sum of hte first n terms")/("the sum of the next n terms")` `=((n)/(2)[2a + (n -1)d])/((n)/(2) [(2(a +nd)+(n-1)d)]]= (2a-d+nd)/( 2a-d+3nd)` `=(1)/(3)` if `d=2a` |
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