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In an AC circuit, resistance 50 Ω, inductance 0.3 H and capacitance 15 μF is connected to an AC voltage source 25 V, 50 Hz. Determine the impedance in the circuit.(a) 110 ohm(b) 100 ohm(c) 125 ohm(d) 140 ohm |
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Answer» The correct answer is (c) 125 ohm Explanation: Z^2 = R^2+(XL-XC)^2, XL=2πfL, XC=1/(2πfC) f=50Hz and L=0.3H and C=15 μF XL=2π(50)(0.3)= 94.25 ohm . XC=1/(2π*50*15*10^-6) = 212.21 ohm. Z^2=50^2+(212.21-94.25)^2=15625 Z = 125 ohm. |
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