InterviewSolution
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InterviewSolution
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In an `AC` circuit, `V` and `I` are given by `V=100sin(100t)volts, I=100sin(100t+(pi)/3)mA`. The power dissipated in circuit isA. `10^(4)`WB. 10 WC. 2.5 WD. 5 W |
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Answer» Correct Answer - C Voltage amplitude m `underset(o)(V)` = 100 V, current amplitude `underset(o)(i)` = 100 mA = `100 xx 10^(-3)` A and phase difference between I and V is `phi` = `pi`/3 = `60^(@)` . Now power dissipated is given by P = `underset(o)(V)``underset(o)(i)`/2 cos`phi` = `100 xx 100 xx 10^(-3) / 2 xx cos 60^(@)` = 2.5 W |
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