1.

In an acute angle △ABC,2cosA=sinBsinC​ and 2tan2B is a solution of the equation x2−9x+8=0, then the distance between incentre to the circumcentre of △ABC is

Answer»

In an acute angle ABC,2cosA=sinBsinC​ and 2tan2B is a solution of the equation x29x+8=0, then the distance between incentre to the circumcentre of ABC is



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