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In an acute angle △ABC,2cosA=sinBsinC and 2tan2B is a solution of the equation x2−9x+8=0, then the distance between incentre to the circumcentre of △ABC is |
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Answer» In an acute angle △ABC,2cosA=sinBsinC and 2tan2B is a solution of the equation x2−9x+8=0, then the distance between incentre to the circumcentre of △ABC is |
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